Question

check the correctness of the relation v^2 - u^2 = 2as , where u is the inital velocity of a particle and v is its final velocity after travelling distance s under uniform acceleration a

Answer 1

Answer:

To check the correctness of physical equation, v² = u² + 2as, Where 'u' is the initial velocity, 'v' is the final velocity, 'a' is the acceleration and s is the displacement. From (1) and (2) we have [L.H.S.] = [R.H.S.] Hence by the principle of homogeneity the given equation is dimensionally correct

Answer 2

Explanation:

the above question shows the relation between u, v, a and s

we have,

v=u+at----1

s=u+v/2*t-----2

putting the value of the from equation 1 and in equation 2,

s=u+v/2 *v-u/a (since we have V=u +at

or,t=v-u/a)

or, s=v2-u2 /2a

or, s=v2-u2=2as

or,v2=u2+2as

therefore,v2-u2=2as

so we can say that the above relation is correct