Check the correctness of the relation V²–U²=2as when U is the initial velocity after travelling a distance ‛s’ under uniform acceleration ‛a’
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Answer:MARK BRAINIEST
Explanation:
We have v
2
−u
2
=2as.
Checking the dimensions on both sides, we get
LHS=[LT
−1
]
2
−[LT
−1
]
2
=[L
2
T
−2
]−[L
2
T
−2
]=[L
2
T
−2
]
RHS=[L
1
T
−2
][L]=[L
2
T
2
]
Comparing LHS and RHS, we find LHS = RHS.
Hence, the formula is dimensionally correct.
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