Check the correctness of v square= vnot square+2ax
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This can be done by dimensional analysis.
Here, v,v0 are velocities. So, their dimensional formula is [LT^-1]
D F of acceleration is [LT^-2]
So, DF of 2as is [LT^-2][L] = [L^2 T^-2]
DF of v²-v0² = L²T^-2
So, DF of both LHS and RHS is same
Hence, it correct
Here, v,v0 are velocities. So, their dimensional formula is [LT^-1]
D F of acceleration is [LT^-2]
So, DF of 2as is [LT^-2][L] = [L^2 T^-2]
DF of v²-v0² = L²T^-2
So, DF of both LHS and RHS is same
Hence, it correct
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