Question

Check the dimension . of consistency of the following equation FS=1/2mv2 - 1/2mu2​

Answer 1

Explanation:

The dimension of L.H.S. F.s = [MLT-2 ].[L] =[ML2T-2 ] The dimensions of R.H.S. .12mv2 or 12mu 212mvn2 or 12mu 2 = [M][LT-1]2 = [ML2T-2] .So, dimensions of L.H.S.= R.H.S. So, given equation is dimensionally correct.

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