Question

check the dimension of the equation
v2 = vo 2 + 2ax​

Answer 1

Answer:

We have v

2

−u

2

=2as.

Checking the dimensions on both sides, we get

LHS=[LT

−1

]

2

−[LT

−1

]

2

=[L

2

T

−2

]−[L

2

T

−2

]=[L

2

T

−2

]

RHS=[L

1

T

−2

][L]=[L

2

T

2

]

Comparing LHS and RHS, we find LHS = RHS.

Hence, the formula is dimensionally correct

Explanation:

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