Physics, asked by antonybinu, 6 months ago

Check the dimensional consistency of Fx = Pv

Answers

Answered by nirman95
5

To check:

Dimensional consistency of the given equation:

(Fx = Pv)

Solution:

For DIMENSIONAL ANALYSIS , we need to separately check the dimensions of the quantities on LHS AND RHS and check their consistency.

LHS:

 \therefore \:  \bigg \{F \times x \bigg \} =  \bigg \{force \times displacement \bigg \}

 \implies\:  \bigg \{F \times x \bigg \} =  \bigg \{ ML{T}^{ - 2} \times L \bigg \}

 \implies\:  \bigg \{F \times x \bigg \} =  \bigg \{ M{L}^{2} {T}^{ - 2}  \bigg \}

RHS:

 \therefore \:  \bigg \{P \times v \bigg \} =  \bigg \{pressure \times velocity\bigg \}

 \implies\:  \bigg \{P \times v \bigg \} =  \bigg \{ M{L}^{ - 1} {T}^{ - 2} \times L{T}^{ - 1} \bigg \}

 \implies\:  \bigg \{P \times v \bigg \} =  \bigg \{ M{L}^{0} {T}^{ - 3}\bigg \}

 \boxed{ \bold{ \therefore \: LHS \:  \neq \:  RHS}}

Hence , the equation is dimensionally inconsistent.

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