Question

Check the dimensional consistency of H=v2sin2teetha divided by 2g​

Answer 1

Answer:

let theeta be ∆

H=v²sin²∆/2g––––>(1)

dimensions:

v² =[M⁰L¹T^-¹]² = [L²T^-²]

sin²∆ = no dimensions

g=[M⁰L¹T^-²]

H=[L¹]

v²sin²∆/2g =[L²T^-²]/[L¹T^-²] =[L¹]

hence proved the dimensional consistency