Question

. Check the dimensional consistens
of equation v= √2gh​

Answer 1

Explanation:

dimensional formula of velocity =[M°LT]

and of g=[M°LT^2]

h=[L]

r.h.s=[M°L^2T^2] hence equation is incorrect

Answer 2

Answer:

Yes, it is correct.

Explanation:

Lets write all the Dimensional formulas

v=[$LT^{-1}$]-(i)

g=[$LT^{-2}$] -(ii)

h=[$L$] -(iii)

the given equation is:

v=$\sqrt{2gh}$-(iv)

substitute (ii) & (iii) in (iv)

v=$\sqrt{LT^{-2}.{L} }$

=$\sqrt{L^{2} T^{-2} }$

=$LT^{-1}$= v =[$LT^{-1}$]

$Hence$ $proved$

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