Question

check the dimensional correctness of theequation : 1/2 mv2= mgh​

Answer 1

Answer:

This is the answer, bruh.

Answer 2

Answer:

$\frac{1}{2} m {v}^{2} = m \times {velocity}^{2} \\ = m { ({l}^{1} \times {t}^{ - 1} ) }^{2} \\ = {m}^{1} {l}^{2} {t}^{ - 2}$

similarly mgh is potential energy dimensions of energy are M1L2T-2

Explanation:

SO the dimensions of potential energy and kinetic energy are same