Question

check the divisibility conditions of 5 and 7 is 555555 in divisibility condition of 7
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Answer 1

Answer:

555,555 is divisible by both the numbers.

Step-by-step explanation:

To see if a number is completely divisible by another number, we must know its divisibility rule,

For 5, the divisibility rule is,

A number is completely divisible by 5 if it ends with 0 or 5.

Here,

555,555 ends with 5 so it is surely divisible by 5.

555,555 ÷ 5 = 111,111

Now,

There is no, as such, a divisibility rule for 7, but we can still find it out using some multiplication and subtraction.

But to define the divisibility rule for 7, we can say,

A number is divisible by 7, if its doubled units digit subtracted from the rest of the number gives a multiple of 7, and we can continue this till we get a small digit, the multiples can also be negative.

For ex:- 497

So, doubled units digit = 2 × 7 = 14

Now,

49 - 14 = 35

Again,

Doubled units place = 2 × 5 = 10

So,

3 - 10 = -7

Thus, it is divisible by 7

Here, we have 555,555

So,

55,555 - (2 × 5) = 55,555 - 10

= 55,545

Again,

5,554 - (2 × 5) = 5,554 - 10

= 5,544

Again,

554 - (2 × 4) = 554 - 8

= 546

Again,

54 - (2 × 6) = 54 - 12

= 42

Again,

4 - (2 × 2) = 4 - 4

= 0

We know that, 0 is a multiple of 7.

Thus,

555,555 is divisible by 7

555,555 ÷ 7 = 79,365

Hope it helped and believing you understood it........All the best