Question

check the divisibility conditions of 7,11 for the following numbers i) 342384 ii)95018 with problem
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Answer 1

Answer:

For 7

1= The condition applies

2=

For 11

1= It doesn't apply

2=It applies

Step-by-step explanation:

For 7: Take the last digit off the number, double it and subtract the doubled number from the remaining number.If the result is evenly divisible by 7 (e.g. 14, 7, 0, -7, etc.), then the number is divisible by seven.

#Last digit=4

Its double=4*2=8

Subtract=34238-8=34230

##Last digit=0

Its double=0*2=0

Subtract=3423-0=3423

###Last digit=3

Its double=3*2=6

Subtract=342-6=336

####Last digit=6

Its double=6*2=12

Subtract=33-12=21

#####Last digit=1

Its double=1*2=2

Subtract=2-2=0

The test succeeds .

For 11=If the difference of the sum of alternative digits of a number is divisible by 11 then that number is divisible by 11 completely.

Group the alternative digits i.e. digits which are in odd places together and digits in even places together. Here 328 and 434 are two groups.

Take the sum of the digits of each group i.e.3+2+8=13 and 4+3+4= 11

Now find the difference of the sums; 13-11=2

If the difference is divisible by 11, then the original number is also divisible by 11. Here 2 is the difference which is not divisible by 11.

Therefore, 342384 is not divisible by 11.