Check the divisibility of 36,825 by 2, 3, 4, 5, 6, 9 and 10. Mention rules of divisibility also.
Answers
36,825 are divisible with 3 and
36,825 are divisible by. 5 also
divisibility rules :
2 : no must hv 2,4,6,8,0 at the end , for eg 24 which has 4 at the end making it divisible by 2
3 : sum of nos must be a multiple of 3 , for eg 30
who's sum of digits is 3+0=3 and 3 is divisible by 3 so 30 is divisible by 3
4 : no must hv 2 zeroes in the end or the last 2 must b divisible by 4 for eg, 644 or 600 both hv last 2 digits as 44 and 00 respectively making them divisible by 4
5 : no must hv 5 or 0 at the end, eg 625 ,has 5 at end so divisible by 5
6 : no must b divisible both by 2 and 3 for eg , 36 ,6,12 etc
7 : We need to double the last digit of the number and then subtract it from the remaining number. If the result is divisible by 7, then the original number will also be divisible by 7.
for eg , 357. Double the 7 to get 14. Subtract 14 from 35 to get 21, which is divisible by 7, and we can now say that 357 is divisible by 7.
8 : If the hundreds digit is even, the number formed by the last two digits must be divisible by 8 for eg, 8 it can b represented as 008 where hundreds digit is 0 which is even hence making 8 divisible by 8
9 : if the sum of the digit of a no is divisible by 9 then the no is also divisible, for eg 9 who's sum of digits =0+9=9 which is divisible by 9 hence the no is also divisible by 9
10 : if the last digit is 0 as in 10,20,30,.....etc
11 : Subtract the last digit from a number made by the other digits. If that number is divisible by 11 then the original number is, too. for eg 121 where , 12-1=11 making it divisible
.........now pls do the sums ..I m sure u will b able to do it all correctly