Check the divisibility of the first number ( divided) by the second number ( divisor ) ( a) 8545 by 5 ( b) 3979 by 3
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We need to find if the first number x is divisible by all prime divisors of y. ... 75 = 3*(5^2) 120 is divisible by both 3 and 5 which are the prime divisors of 75. ... b) If GCD > 1, the GCD contains prime divisors which divide x also.
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