Question

check the divisibility test for 2,3,4,5,9 for numbers from 2000 to 2015 .​

Answer 1

Step-by-step explanation:

2000

digit in Units place is 0

2000 is divisible by 2

sum of the digits 2

so it is not divisible by 3

number formed by last two digits is zero

it is divisible by 4

units digit is zero

so 2000 is divisible by 5

sum of digits is 2

it is not divisible by 9

so 2000 is not divisible by 9

2001

digit in Units place is 1

2001 is not divisible by 2

sum of the digits 3

so 2001 is divisible by 3

number formed by last two digits is 01

2001 is not divisible by 4

units digit is 1

so 2001 is not divisible by 5

sum of digits is 3

it is not divisible by 9

so 2001 is not divisible by 9

2002

digit in Units place is 2

2002 is divisible by 2

sum of the digits 4

so 2001 is not divisible by 3

number formed by last two digits is 02

2002 is not divisible by 4

units digit is 2

so 2002 is not divisible by 5

sum of digits is 4

it is not divisible by 9

so 2002 is not divisible by 9

2003

digit in Units place is 3

2003 is not divisible by 2

sum of the digits 5

so 2003 is not divisible by 3

number formed by last two digits is 03

2003 is not divisible by 4

units digit is 3

so 2003 is not divisible by 5

sum of digits is 5

it is not divisible by 9

so 2003 is not divisible by 9

2004

digit in Units place is 4

2004 is divisible by 2

sum of the digits 6

so 2004 is divisible by 3

number formed by last two digits is 04

2004 is divisible by 4

units digit is 4

so 2004 is not divisible by 5

sum of digits is 6

it is not divisible by 9

so 2004 is not divisible by 9

2005

digit in Units place is 5

2005 is not divisible by 2

sum of the digits 7

so 2005 is not divisible by 3

number formed by last two digits is 05

2005 is not divisible by 4

units digit is 5

so 2005 is divisible by 5

sum of digits is 7

it is not divisible by 9

so 2005 is not divisible by 9