Check the equation
V
=
KA’ut, where A' is the area of cross section of the pipe, u is the speed of flow, t is the time, V is the volume of water flowing through the pipe and K is a dimensionless constant. State whether the equation is correct or not.
Answers
Answered by
0
Answer:
M°L°O°
Explanation:
V=kavt
Let k=M
α
L
β
T
γ
M
0
L
3
T
0
=(M
α
L
β
T
γ
)(L
2
)(LT
−1
)(T)
M
0
L
3
T
0
=M
α
L
β+2+1
T
γ+0
γ=0
α=0
β+3=3 ⇒β=0
Hence, k=M
0
L
0
T
O
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