check the given numbers are the solution for the equation :
(4x+5)-(x-2)=15 or not (x=(-1),(+2) and (-3)
Answers
Answered by
1
x=-1
{4(-1)+5}-{(-1)-2}
{-4+5}-{-3}
1+3
4
x=2
{4(2)+5}-{2-2}
8+5-0
13
x=-3
{4(-3)+5}-{(-3)-2}
{-12+5}-{-5}
-7+5
-2
so none give 15
{4(-1)+5}-{(-1)-2}
{-4+5}-{-3}
1+3
4
x=2
{4(2)+5}-{2-2}
8+5-0
13
x=-3
{4(-3)+5}-{(-3)-2}
{-12+5}-{-5}
-7+5
-2
so none give 15
manish2005:
Your very intelligent and I even marked in brainiest
Answered by
0
To know whether they are the solutions or not,put x value in the given,
Put x = -1
[4(-1)+5-(-1-2)] = 15
-4+5+1+2 = 15
4 ≠ 15
It is not solution
Put x=2,
[4(2)+5-(2-2)] = 15
8+5-0 = 15
13 ≠ 15
It is not solution,
Put x= -3
[4(-3)+5-(-3-2)] = 15
-12+5+3+2 = 15
-2 ≠ 15
It is not a solution.
Put x = -1
[4(-1)+5-(-1-2)] = 15
-4+5+1+2 = 15
4 ≠ 15
It is not solution
Put x=2,
[4(2)+5-(2-2)] = 15
8+5-0 = 15
13 ≠ 15
It is not solution,
Put x= -3
[4(-3)+5-(-3-2)] = 15
-12+5+3+2 = 15
-2 ≠ 15
It is not a solution.
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