Check the physical relation dimensionally correct v = u+at²
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Equation: v = u + at^2
For the given formula to be dimensionally correct, Dimension(LHS) = Dimension(RHS).
So,
Dimension(LHS) = Dimension of (v)
= dimension of velocity
= [LT^-1] ..................................(a)
and,
Dimension(RHS) = Dim(u) + dim(at^2)
= dim(velocity) + dim(acceleration)×dim(time)^2
= [LT^-1] + [LT^-2]×[T^2]
= [LT^-1] + [L] ..........................(b)
.
Now, from (a) and (b) it is clear that
Dimension(LHS) ≠ Dimension (RHS)
Hence, the formula is dimensionally incorrect.
.
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