check the whether the following are quadratic equations (I) (x+2)³=x³-4
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Answered by
1
Given equation is (x+2)3=x3−4.
Applying the algebraic property, (a+b)3=a3+3ab2+3ba2+b3 to solve the given equation further.
⇒x3+6x2+12x+23=x3−4
⇒x3+6x2+12x+23−x3+4=0
⇒6x2+12x+12=0
Here, the highest power of x in the equation is 2.
Hence, it is a quadratic equation
Answered by
1
Answer:
When a, b, and c are real numbers, a ≠ 0 and the discriminant is zero, then the roots α and β of the quadratic equation ax2+ bx + c = 0 are real and equal.
So , equation
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