Question

check weather 6^n can end with digit 0 for any natural number n​

Answer 1

Answer:

yes

Step-by-step explanation:

whenever 6 is multiplied to a multiple of 5 i.e, n= multiple of 5 will result in a number ending with 0

whenever any multiple of 5 is multiplied with any even number the resulting number always ends with 5

for example:

6 × 5= 30

6 x 0= 0

6 x 10= 60

6 x 15= 90

Answer 2

Answer:

hey mate here is your answer....

Step-by-step explanation:

➡️ If any number ends with the digit 6, it should be divisible by 10 or in other word, it will also be divisible by 2 and 5 as 10 = 5x2

➡️ Prime factorization of 6^n = (2 x 3) ^n

➡️ It can be observed that 5 is not in the prime factorization of 6^n

➡️ Hence for any value of n, 6^n will not be divisible by 5.

➡️ Therefore 6^n cannot end with digit 0 for any natural n.

Hope it helps!☺️