Math, asked by rathiseema521, 7 months ago

check weather 6^n can end with digit 0 for any natural number n​

Answers

Answered by Princiafernandez
2

Step-by-step explanation:

If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5

Prime factorisation of 6n = (2 ×3)n

It can be observed that 5 is not in the prime factorisation of 6n.

Hence, for any value of n, 6n will not be divisible by 5.

Therefore, 6n cannot end with the digit 0 for any natural number n.

Similar questions