Question

Check weather 6^n can end with the digit 0 for any natural number n.

Answer 1

Answer:

The value of n, 6n^2 will not be divisible by 5

Explanation:

If any number and sweet digit 0 it should be divisible by 10 or it will be divisible by 2 and 5. The prime factorization of 6 n square= (2×3)^n . It can be observed at five is not factor of 6n^2. So,the value of n, 6n^2 will not be divisible by any natural number n.

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Answer 2

Answer:

If any digit has the last digit 10 that means it divisible by 10.

The factor of 10=2×5,

So value of 6n should be divisible by 2 and 5.

Both 6n is divisible by 2 but not divisible by 5.

So, it can not end with 0.

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