check weather p(x) is a factor of polynomial g(x) by applying division algorithm p(x)=(x-1) g(x) =x2-3x+2
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✌️Hey mate ✌️
let p(x) = (x-1)
so, x -1 = 0
=> x = 1
now, g(x) = x²-3x+2
=> g(1) = (1)²-3(1)+2
=> g(1) = 1-3+2
=> g(1) = -4 ≠ 0
Hence, p(x) = x-1 is not a factor of g(x) = x²-3x+2.
hope it was helpful to you!
let p(x) = (x-1)
so, x -1 = 0
=> x = 1
now, g(x) = x²-3x+2
=> g(1) = (1)²-3(1)+2
=> g(1) = 1-3+2
=> g(1) = -4 ≠ 0
Hence, p(x) = x-1 is not a factor of g(x) = x²-3x+2.
hope it was helpful to you!
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