Question

check weather p(y)=4y3+4y2-y-1.factor of (2y+1)​

Answer 1

Answer:

p(y)=4y3+4y2-y-1

(2y+1)​

2y+1=0

y=-1/2

Now solving using reminder theorem

p(-1/2)=4(-1/2)^3+4(-1/2)^2-(-1/2)-1

= -1/2-1+1/2-1

=0

Therefore the factor (2y+1)​ is a factor of p(y)=4y3+4y2-y-1

Hope this helps you

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