Check weather (x-1) is a factor of the P(X)
Polynomial is in Above Picture
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no it is not a factor of the above equation....
i hope this attachment may help u☺☺
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let x-1 = 0
=> x = 1
now..put the value of x in polynomial
p(x) = x³-x²-(2+√2)x+√2
=> p(1) = 1³-1²-(2+√2)1+√2
=> p(1) = 1-1-2-√2+√2
=> p(1) = 0-2+0
=> p(1) = 2
since p(1) ≠ 0
so (x-1) is not a factor of the p(x) = x³-x²-(2+√2)x+√2
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