Question

Check weather (x-2) is a factor of p(x)=3x4th-4xsquare+8x-1

Answer 1

(x - 2) is not a factor of p(x).

Step-by-step explanation:

$p(x) = 3x^{4} - 4x^{2} + 8x - 1$

We have to check (x - 2) is a factor of p(x).

We plug x = 2 in p(x),

$p(2) = 3(2)^{4} - 4(2)^{2} + 8(2) - 1$

p(2) = 48  - 16 + 16 - 1 = 47

Here p(2) ≠ 0

Hence, (x - 2) is not a factor of p(x).

Answer 2

${p(x)} = {3x}^{4} - {4x}^{2} + {8x} - {1}$

(x-2)=0

x=2

Putting x = 2 in p(x):-

${p(2)} = {3}×{2}^{4} - {4}×{2}^{2} + {8}{2} - {1}$

${p(2)} = {48} - {16} + {16} - {1}$

${p(2)} = {47}$

Since, p(2) ≠ 0

(x-2) is not a factor.