Question

check wether -2 and 2 are the zeroes of ploynomial x⁴-16​

Answer 1

Answer:

Taking x as -2 we have,

= (-2)^4 - 16

= 16 - 16

= 0

Taking x as 2 we have

= (2)^4 - 16

= 16 - 16

= 0

As we have got both the answers as 0 by replacing x as 2 and -2, we can say that these are the zeros of the polynomial

Step-by-step explanation:

Have a nice day my friend :)

Answer 2

$(x + 2)(x - 2) = {x}^{2} - 2x + 2x - 4 \\ = {x}^{2} - 4 \\ divide \: {x}^{4} - 16 \: by \: {x}^{2} - 4 \\ if \: the \: remainder \: is \: 0 \: then \: - 2and \: 2are \: the \: zeroes \: of \: {x}^{4} - 16$