check wether the equation 5x^2-6x -2 = 0 has real roots if yes find them by quadratic formula.
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Explanation :-
We know that for a quadratic equation
ax^2 + bx + c = 0 , discriminant b^2 - 4ac
• If b^2 - 4ac > 0 having two distinct roots
• If b^2 - 4ac = 0 having equal real roots
• If b^2 - 4ac < 0 having no real roots
Solution :-
5x^2 - 6x - 2
Here a = 5 , b = 6 , c = -2
By using discriminant b^2 - 4ac
= ( 6 )^2 - 4 * 5 * -2
= 36 + 40
= 76 > 0
5x^2 - 6x - 2 having two distinct roots .
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