Math, asked by mamtapatil496, 5 months ago

check wether the equation 5x^2-6x -2 = 0 has real roots if yes find them by quadratic formula.

please urgent.!!

Answers

Answered by Anonymous
15

Explanation :-

We know that for a quadratic equation

ax^2 + bx + c = 0 , discriminant b^2 - 4ac

• If b^2 - 4ac > 0 having two distinct roots

• If b^2 - 4ac = 0 having equal real roots

• If b^2 - 4ac < 0 having no real roots

Solution :-

5x^2 - 6x - 2

Here a = 5 , b = 6 , c = -2

By using discriminant b^2 - 4ac

= ( 6 )^2 - 4 * 5 * -2

= 36 + 40

= 76 > 0

5x^2 - 6x - 2 having two distinct roots .

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