check wether x³ +ax+x+a is a multiple of(x+a)
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Answered by
1
Answer:
no it is not a factor the remainder are -a cube -a sq
Step-by-step explanation:
Answered by
1
Answer:
x³+ax+x+a= a , x+a=0
x³+ax+x+a= a x=-a
-a³+ a(-a)+a=a
-a-a+a=a
-a=a
a+a=2a
= 2a
I hope it is helpful and sufficient for you
Thanks
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