Question

check wheater 6^n can end with the digit zero for any natural number n​

Answer 1

Answer:

see the attachment

Step-by-step explanation:

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Answer 2

Answer:

any no. can have 0 as it's end digit if it is divisible by 10 or 5

on the prime factorisation of 6^n

= (2×3)^n

it doesn't have 5 in its factorisation

so, 6^n can't end with the digit zero for any natural no. n

Step-by-step explanation:

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