Question

Check wheather -3and3 are the zeros of the polynomials x^2-9

Answer 1

Answer:

p(x) = x^2 - 9

=> p(3) = (3)^2 - 9

=> p(3) = 0

=> p(-3) = (-3)^2 - 9

=> p(-3) = 0

.°. Both are zeroes !!

Answer 2

Answer: Yes, both of them are the zeroes of the given polynomial.

Step-by-Step explanation:

For verifying if the given numbers are the zeroes, what we will do is, put the value of x as the number. For instance:

Taking x = 3 :

$\tt{p(x) = x^{2} - 9}$

=> $\tt{p(3) = (3)^{2} - 9}$

When you subtract, you get the value as:

=> p(3) = 0

.°. 3 is a zero of p(x)

Taking x = (-3) :

$\tt{p(x) = x^{2} - 9}$

=> $\tt{p(3) = (-3)^{2} - 9}$

When you subtract, you get the value as:

=> p(-3) = 0

.°. (-3) is a zero of p(x)

Thus, we can say that both the numbers are the zeroes of the given polynomial.