Question

check wheather the method of dimension are correct.
​

Answer 1

(i) correct (ii) correct

Solution :

(i) υ=P/ρ−−−−√

LHS=υ=[LT−1]

RHS=p/ρ−−−−√=ML−1T−2ML−3−−−−−−−−−√=[LT−1]

As LHS = RHS, dimensionally, therefore, the

formula is correct.

(ii) v=2π(Ig)

LHS=v=[T−1]

RHS=2πIg−−√=LLT−2−−−−−√v=[T]

As LHS≠RHS, dimensionally, therefore the

relation is not correcAnswer:

i hope this will help you

if yes make me brainlyest

Explanation:

Answer 2

Answer:

the above answer is the correct one....

so itna poora likhne ka koi matlab hai nahi....