Question

Check wheather (x-1) is a factor of the polynomials x^3-27x^2+8x+18

Answer 1

g(x)= x-1
0 = x-1
x=1
Put x=1 in P(x)
${x}^{3} - 27( {x}^{2} ) + 8x + 18 \\ {(1)}^{3} - 27( {1}^{2} ) + 8(1) + 18 \\ 1 - 27 + 8 + 18 \\ 27 - 27 \\ = 0$
Since No reminder is left so yes x-1 is a factor.