Music, asked by e5629, 6 months ago

check wherher the following


equation (x? 2)^3 = 2x(x^2-1)​

Answers

Answered by vishujangade001
2

Answer:

+bx+c=0.

Explanation:

We know that the general form of quadratic equation is ax  

2

+bx+c=0.

The given equation is (x+2)  

3

=2x(x  

2

−1) can be simplified as follows:  

(x+2)  

3

=2x(x  

2

−1)

⇒x  

3

+2  

3

+(3×x×2)(x+2)=2x  

3

−2x(∵(a+b)  

3

=a  

3

+b  

3

+3ab(a+b))

⇒x  

3

+8+6x(x+2)=2x  

3

−2x

⇒x  

3

+8+6x  

2

+12x=2x  

3

−2x

⇒x  

3

+8+6x  

2

+12x−2x  

3

+2x=0

⇒−x  

3

+6x  

2

+14x+8=0

Since the variable x in the equation −x  

3

+6x  

2

+14x+8=0 has degree 3, therefore, it is not of the form ax  

2

+bx+c=0.

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