Question

Check whether (0,5) (4,2)(3,-5) are slovents of 2x+3y=15

Answer 1

Answer:

(i)

$x = 0 \\ y = 5 \\ 2x + 3y = 15 \\ 2(0) + 3(5) = 15 \\ 0 + 15 = 15 \\ 15 = 15$

Thus, the first set of values are a solution for the given equation.

(ii)

$x = 4 \\ y = 2 \\ 2x + 3y = 15 \\ 2(4) + 3(2) = 15 \\ 8 + 6 = 15 \\ 14 < 15$

Thus, the second set of values aren't a solution for the given equation.

(iii)

$x = 3 \\ y = - 5 \\ 2x + 3y = 15 \\ 2(3) + 3( - 5) = 15 \\ 6 - 15 = 15 \\ - 9 < 15$

Thus, the third set of values aren't a solution of the given equation.

Hope this helps.

Thanks.