Check whether 1, -1 are the zeroes of p(x) = x²-1 or not
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Step-by-step explanation:
p(x) = x² - 1
p(1) = 1² - 1 = 1 - 1 = 0
p(-1) = (-1)² - 1 = 1 - 1 = 0
1 and -1 are zeros of x² - 1
hope you get your answer
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