Question

check whether 1,-1 are the zeros of x²-1​

Answer 1

Answer:

${x}^{2} - 1 \: is \: in \: the \: \\ form \: of \: {a}^{2} - {b}^{2} \: = a + b \times a - b \\ so \: \\ - 1and \: 1 \: are \: the \: roots$

Answer 2

Answer:

p(x)= x^2-1

p(1)= (1)^2-1

= 1-1

= 0

p(-1)= (-1)^2 -1

= 1-1

= 0

Yes 1, -1 are zeroes of x^2-1.

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