Check whether -1, 1 are zeroes of
+ 3x - 1 or not
2.
P(x) = x2
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Answer:
No, -1 and 1 are not the zero's of p(x).
Step-by-step explanation:
put x=-1
p(-1)=(-1)^2 +3*(-1)-1
=1-3-1
= -3
Therefore, -1 is not the zero of p(x)
put x=1
p(1)=(1)^2+3*(1)-1
=1+3-1
=3
Therefore,1is not the zero of p(x)
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