Question

Check whether 1 ³, 2³ , 3³ ........are in ap

Answer 1

for them to be in AP

2³-1³ = 3³- 2³

8 - 1 = 27 - 8

7 ≠ 19

hence they are no in AP

Answer 2

Answer:

1^3 = 1*1*1= 1

2^3 = 2*2*2 = 8

3^3 = 3*3*3 = 27

a2-a1 = d

8 - 1 = 7

a3-a2=a2-a1

27-8=8-1

21 not = 7

therefore it doesn' t form an AP

hence proved

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