Check whether 1 and 1 are the zeroes of the polynomial x2+x-2
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first let us assume that p(x) =1
so, now substitute 1 in the place of x ..
1^2+1-2 = 0
1 + (-1) =0
1-1 =0
0=0
so if l
LHS = RHS
1 and 1 are the zeroes of the given polynomial.
Hope that answers your question!
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