Question

Check whether 12n can end with digit 0 for any natural number n . give justification

Answer 1

Here, Number=12^n where n stand for any natural number .

Now 12^n= (2^2 x3)^n

Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12ncannot end with the digit 0 or 5.

Hope it helps.

Answer 2

Answer:

it cannot end with digit 0 because it contains the factors of 2 and 3 , not 2 and 5

It contains 2 and 3

so it cannot end with digit 0

Step-by-step explanation:

12=2×2×2

if any no. has prime factorisation of 2 and 5

so a no. can end with digit 0

hope it helps u mate..........

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