check whether 12n ends with the digit 0 for any natural number.
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Here number =12^n where n stand for any natural number
Now 12^n=(2×2×3)^n
Now for 12^n to ens with 0 it should have 2 as well as 5 in its prime factors to end with 0 ,Also to end with 5 it requires at least a single a single multiple of 5 in its prime factors
So 12,cannot end with the digit 0 .
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