Question

check whether 140 is a term of AP - 7 - 4 - 1 - 2​

Answer 1

Answer:

a=--7

d = a2-a1

=-4-(-7)

=3

len 140 be the term of ap

an= a+(n-1)d

140=-7+3n-3

3n=150

n=30

so 140 be the 30th of Ap

Answer 2

The 50th term of an AP is 140.

Step-by-step explanation:

The given AP are:

- 7, - 4,  - 1,  2​

Here, first term(a) = - 7, common difference (d) = - 4 + 7 = 3 and $a_{n} =140$

Let nth term be the 140.

To check whether 140 is a term of AP or not.

We know that,

The nth term of an AP.

$a_{n} =a+(n-1)d$

⇒ - 7 + (n - 1)3 = 140

⇒ (n - 1)3 = 140 + 7 = 147

⇒ n - 1 = $\dfrac{147}{3}$ = 49

⇒ n = 49 + 1 = 50

∴ The 50th term of an AP is 140.

Thus,  the 50th term of an AP is 140.