check whether - 141 is a term of the AP 11,8,5,2............................. .........................?
Answers
Answer:
AP is 11, 8, 5, 2, …. We need to check whether – 150 is a term of AP
Lets assume it is nth term of AP
So, an = –150 Also,
a = 11, d = 8 – 11 = –3 Now,
an = a + (n – 1) d
Putting values – 150 = 11 + (n – 1) × – 3 – 150 = 11 + n (- 3) – 1 × ( – 3) – 150 = 11 – 3n + 3 – 150 = 14 – 3n – 150 – 14 = – 3n – 164 = – 3n (−164)/(− 3) = n 164/3 = n 54.33 = n
n = 54.33
Since n is coming in decimal Hence, – 150 is not term of AP.
HOPE IT WILL HELP YOU.
Step-by-step explanation:
☺ Hello mate__ ❤
◾◾here is your answer...
Let −150 is the nth of AP 11,8,5,2...
which means that an'=−150
Here, First term = a = 11
Common difference = d = 8 - 11 = -3
Using formula an'=a+(n−1)d,
to find nth term of arithmetic progression, we get
−150=11+(n−1)(−3)
⇒−150=11−3n+3
⇒3n=164
⇒n=164/3
But, n cannot be in fraction. Therefore, our supposition is wrong. −150 cannot be term in AP.
I hope, this will help you.
Thank you______❤
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Answer:
nv check whether - 141 is a term of the AP 11,8,5,2............................. .........................?