Question

Check whether-150 is a term of a ap : 11,8,5,2....

Answer 1

Answer:

an = a + (n-1)d

-150 = 11 +(n-1)(-3)

-150 = 11 - 3n + 3

-150 = 14 - 3n

3n = 164

n = 164 / 3

n = 52.66

as n is in decimal form and therefore -150 is not a term of ap

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Answer 2

☆Given:

• Arithmetic progression series:

11 , 8 , 5 , 2 ....

☆ To check:

➡ whether t - 150 is a term in the given AP.

☆Formula used:

¤ tn = a + ( n - 1 ) d

where a ➡ first term

n ➡ Number of terms

d ➡ Common difference

Given is the t -150;

Lets substitute in the above formula,

- 150 = 11 + ( n - 1 ) (-3)

[ Here a is the first term and d is the second term - first term]

-150 = 11 -3n+3

-150 = 14 -3n

-3n = - 164

=> n = 164/3 = 54.6

Since The remainder Is not zero, it can't be the term of the given arithmetic series.

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