Question

Check whether - 150 is a term of the A.P: 11, 8, 5, 2,
If not a term, find the least value to
be added to the number, it will be exist in the A.P.​

Answer 1

Answer:

-150 = a + ( n - 1) d

-150 = 11 + ( n - 1 )(-3)

-150 = 11 - 3n +3

3n = 150+11+3

3n = 164

n = 164/3

- 150 is not a term of the A. P : 11,8,5,2.

-1 is the least value that should be added to the number (-150) so that it will exist in the A. P.

that it will exist in the A. P.( -1)+(-150) = -151

-151 = a + (n- 1) d

-151 = 11 + (n -1) (-3)

-151 = 11-3n +3

3n = 151+11+3

3n = 165

n = 165/3

n = 55

-151 will be the 55th term of the A. P. 11,8,5,2.

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Answer 2

Answer:

-150 is not in A.P

Step-by-step explanation:

A.P = 11, 8, 5, 2

a = 11, d = 8-11=-3, $a_{n}$ = -150

$a_{n}$ = a+(n-1)d

-150= 11+(n-1)(-3)

-150= 11-3n+3

-150= 14-3n

-150-14= -3n

-164= -3n

    n = -164/-3

Therefore, its not an integer, i.e, its not an A.P

The least value added in -150 is -1

because $a_{55}$ = -151

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