Check whether -150 is a term of the AP 11,8,5,2,••••
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Answered by
0
Step-by-step explanation:
In APs, nth term = a + ( n - 1 )d, a is first term and d is common difference.
Here,
First term = 11
Com. Dif. = 8 - 11 = - 3
If - 150 is in AP, let it be nth term of AP.
= > 11 + (n - 1)(-3) = - 150
= > (n - 1)(-3) = - 150 - 11 = - 161
= > n - 1 = - 161/(-3) = 161/3
= > n - 1 = 53.6
= > n = 54.6
As n is a decimal number, - 150 is not in this AP.
Answered by
27
a = 11
d = 8-11 = -3
Let aₙ = -150
∴ If n is a positive integer then -150 will be the term of the AP.
aₙ = a + (n-1) d = -150
a + (n-1) d = -150
11 + (n-1)(-3) = -150
-3(n-1) = -150-11
-3(n-1) = -161
n-1 = -161/-3
n-1 = 53.67
n = 53.67+1
n = 54.67
As n ≠ positive integer, therefore -150 is not a term of the AP = 11,8,5,2,...
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