Question

Check whether, –150 is a term of the AP : 11, 8, 5, 2 . . .

Answer 1

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Answer 2

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A. P :- 11, 8, 5, 2...........

a = 11

d = 8 - 11 = -3

an = -150

$\huge{\boxed{\red{\sf{an = a + (n - 1)d}}}}$

Put Values

-150 = 11 + (n - 1)-3

⟹ -150 = 11 - 3n + 3

⟹ -150 = 14 - 3n

⟹ -150 - 14 = -3n

⟹ -164 = -3n

⟹ 164 = 3n

⟹ 164/3 = n

We know that, n can't be integer. So,

It is not the term of A. P