Question

check whether -150 is a term of this A.P. : 11, 8, 5, 2 or not

Answer 1

Answer:

Step-by-step explanation:

There is a photo of solutions

Answer 2

$a = 11 \\ d =8 - 11 = - 3 \\ let \: - 150 \: be \: a \: term \: of \: an \: ap \\ \\ - 150 = a + (n - 1)d \\ - 150 = 11 + (n - 1)( - 3) \\ - 150 - 11 = (n - 1)( - 3) \\ - 161 = 3 - 3n \\ 161 + 3 = 3n \\ 164 = 3n \\ \frac{164}{3} = n$

n=54.66

it's not possible ...so, -150 is not the term of an AP...

hope it helps you out ☺✌✌