Question

check whether _150 is an term of the ap : 11,8,5,2

Answer 1

AP is 11, 8, 5, 2, …. We need to check whether – 150 is a term of AP
Lets assume it is nth term of AP
So, an = –150 Also,
a = 11, d = 8 – 11 = –3 Now,
an = a + (n – 1) d
Putting values – 150 = 11 + (n – 1) × – 3 – 150 = 11 + n (- 3) – 1 × ( – 3) – 150 = 11 – 3n + 3 – 150 = 14 – 3n – 150 – 14 = – 3n – 164 = – 3n (−164)/(− 3) = n 164/3 = n 54.33 = n
n = 54.33

Since n is coming in decimal Hence, – 150 is not term of AP.

HOPE IT WILL HELP YOU.

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

Let −150 is the nth of AP 11,8,5,2...     

which means that  an'=−150

Here, First term = a = 11

Common difference = d = 8 - 11 = -3

Using formula an'=a+(n−1)d,  

to find nth term of arithmetic progression, we get

−150=11+(n−1)(−3)

⇒−150=11−3n+3

⇒3n=164

⇒n=164/3

But, n cannot be in fraction. Therefore, our supposition is wrong. −150 cannot be term in AP.

I hope, this will help you.

Thank you______❤

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