Math, asked by borahsangeeta26, 5 months ago

check whether -150 is term of AP 11,8,5,2​

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Answered by rudrabhoutmange
5

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Answered by XxCharmingGuyxX
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AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161⇒−3n=−164⇒n=54

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161⇒−3n=−164⇒n=54 3

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161⇒−3n=−164⇒n=54 32

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161⇒−3n=−164⇒n=54 32

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161⇒−3n=−164⇒n=54 32

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161⇒−3n=−164⇒n=54 32 Since, n is not a natural number.

AnswerClearly, the given Sequence is an AP with first term a=11 and common difference d=8−11=−3.Let −150 be the nth term of the given AP.⇒a n =−150⇒a+(n−1)d=−150⇒11+(n−1)×−3=−150⇒(n−1)×−3=−161⇒−3n+3=−161⇒−3n=−164⇒n=54 32 Since, n is not a natural number.Hence, −150 is not any term of given AP.

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